Algebra Problem Again..Help?
Anthony leaves his ouse on his bike traveling at 18 mph. Thirty minutes later, his brother chandler takes after him at 24 mph. How long will it take chandler to catch upto Anthony?
Mathematics - 2 Answers
People's Answers, Critics, Comments, Opinions :
Answer 1 :
rate times time equal distance, and they travel the same distance. Let t=Anthony's time in hours. Let t-.5 = Chandler's time in hours. 18t = 24(t-.5) 18t = 24t - 12 12 = 6t t = 2 hours
Answer 2 :
Hours Chandler catches up (x): 18(x + 1/2) = 24x 18x + 9 = 24x 6x = 9 x = 9/6 or 3/2 or 1 1/2 Answer: 1 1/2 hours Chandler catches up with Anthony. Proof (equal distance traveled): 18 mph(1 1/2 + 1/2 hrs) = 24 mph(1 1/2 hrs) 18 mph(3/2 + 1/2 hrs) = 24 mph(3/2 hrs) 18 mph(4/2 hrs) = 36 mi 18 mph(2 hrs) = 36 mi 36 mi = 36 mi
Anthony leaves his ouse on his bike traveling at 18 mph. Thirty minutes later, his brother chandler takes after him at 24 mph. How long will it take chandler to catch upto Anthony?
Mathematics - 2 Answers
People's Answers, Critics, Comments, Opinions :
Answer 1 :
rate times time equal distance, and they travel the same distance. Let t=Anthony's time in hours. Let t-.5 = Chandler's time in hours. 18t = 24(t-.5) 18t = 24t - 12 12 = 6t t = 2 hours
Answer 2 :
Hours Chandler catches up (x): 18(x + 1/2) = 24x 18x + 9 = 24x 6x = 9 x = 9/6 or 3/2 or 1 1/2 Answer: 1 1/2 hours Chandler catches up with Anthony. Proof (equal distance traveled): 18 mph(1 1/2 + 1/2 hrs) = 24 mph(1 1/2 hrs) 18 mph(3/2 + 1/2 hrs) = 24 mph(3/2 hrs) 18 mph(4/2 hrs) = 36 mi 18 mph(2 hrs) = 36 mi 36 mi = 36 mi
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